2026-01-07 11:11:18 +0300 MSK
Maximum Product of Splitted Binary Tree
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Code
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def maxProduct(self, root: Optional[TreeNode]) -> int:
if root is None:
return 0
sums = {}
def dfs_sum(node: Optional[TreeNode]) -> int:
if node is None:
return 0
node_id = id(node)
if node_id in sums:
return sums[node_id]
res = node.val + dfs_sum(node.left) + dfs_sum(node.right)
sums[node_id] = res
return res
dfs_sum(root)
root_sum = sums[id(root)]
def dfs(node: Optional[TreeNode]) -> int:
if node is None:
return 0
tree1 = sums[id(node)]
tree2 = root_sum - tree1
res = max(tree1 * tree2, dfs(node.left), dfs(node.right))
return res
return max(dfs(root.left), dfs(root.right)) % (10 ** 9 + 7)