2025-12-24 13:58:01 +0300 MSK
Path Sum II
Links
Code
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def pathSum(self, root: Optional[TreeNode], targetSum: int) -> List[List[int]]:
res, cur = [], []
def dfs(node: Optional[TreeNode], cur_sum: int) -> None:
if node is None:
return
cur_sum += node.val
cur.append(node.val)
if node.right or node.left:
dfs(node.left, cur_sum)
dfs(node.right, cur_sum)
elif cur_sum == targetSum:
res.append(cur.copy())
cur.pop()
dfs(root, 0)
return res