2026-01-10 12:28:57 +0300 MSK
Find Users with High Token Usage
Links
Code
SELECT
user_id,
COUNT(prompt) AS "prompt_count",
ROUND(AVG(tokens),2) AS "avg_tokens"
FROM
prompts
GROUP BY
user_id
HAVING
COUNT(prompt) > 2
AND MAX(tokens) > AVG(tokens)
ORDER BY
avg_tokens DESC,
user_id;