2025-10-01 09:19:12 +0300 MSK
Majority Frequency Characters
Links
Code
class Solution:
def majorityFrequencyGroup(self, s: str) -> str:
freqs = [0] * 26
groups = [([], 0) for _ in range(101)]
for char in s:
freqs[ord(char) - 97] += 1
for i, freq in enumerate(freqs):
if freq == 0:
continue
chars, _ = groups[freq]
chars.append(chr(i + 97))
groups[freq] = (chars, freq)
groups.sort(key=lambda val: (len(val[0]), val[1]))
return "".join(groups[-1][0])